y = ln(x/m -sa)/ r^2

The friendliest place on the web for anyone that follows U2.
If you have answers, please help by responding to the unanswered posts.
Shit I thought I was the only one, now lets make jokes about aleph null, the smallest of infinite cardinal.
 
A_Wanderer said:
Shit I thought I was the only one, now lets make jokes about aleph null, the smallest of infinite cardinal.

Aleph-null bottles of beer on the wall
Aleph-null bottles of beer
Take one down, pass it around
Aleph-null bottles of beer on the wall

Aleph-null bottles of beer on the wall
Aleph-null bottles of beer
Take one down, pass it around
Aleph-null bottles of beer on the wall

Aleph-null bottles of beer on the wall
Aleph-null bottles of beer
Take one down, pass it around
Aleph-null bottles of beer on the wall

Aleph-null bottles of beer on the wall
Aleph-null bottles of beer
Take one down, pass it around
Aleph-null bottles of beer on the wall

etc.
 
that's incorrect. you went from subtracting sa on one side to multiplying it with m.

and your ry in the left side should be converted to e.

:tsk:

me^(re) = x-m+(sa)

eliminate the m's for balance:

e^(re) = x-m+(sa)

then to solve for x:

x = e^(re)+m-(sa)

solve for m:

m = e^(re)-x-(sa)

solve for s:

sa/a = (e^(re)-x)/a

solve for a:

sa/s = (e^(re)-x)/s

e and r need to be given to solve this i think. i'm not that good at math. :shrug:
 
Last edited:
AcrobatMan said:
y = ln(x/m -sa)/ r^2
yr^2 = ln(x/m-sa)
e^ (yr^2) = x/m - sa
m(e^ (yr^2) + sa ) = x
me^(yr^2) = x-mas
me^(rry) = x-mas

:dance:
:hyper:
:kiss:

AcrobatMan Rocks!!! :up: :applaud:
(Although nightmares of undergraduate math are returning... )
 
Back
Top Bottom